## ☢☢☢ What is an Electron? – In 306 seconds! ☢☢☢

Filed under Radiation, Science
Tagged as , , , , , , ,

More information:
http://en.wikipedia.org/wiki/Electron
http://www.chem4kids.com/files/atom_e…

Detector used in video: SE International Inspector USB
http://geigercounters.com/InspectorUS…

Voice over at start of video by Emily Linard
https://www.fiverr.com/emilylinard

All graphics shown are property of Anti-Proton.com

## ☢ Radioactive Tritium Gun Sight – Tested! ☢

Filed under Radiation, Science
Tagged as , , , , , , , , , ,

☢☢☢ Read Details ☢☢☢
A Glock radioactive gun sight is tested to determine how radioactive it might be!

X-Ray Spectrum of Tritium: http://anti-proton.com/tritium2.png
X-Ray Spectrum of Gun Sight: http://anti-proton.com/tritium_gunsight.png

## Uranium Glassware Shopping!

Filed under Radiation, Science

I journey to Fredericksburg VA to find uranium glassware to buy!

## (Radiation and Geiger Counters) How to Separate Alpha, Beta, Gamma

Filed under Radiation, Science
Tagged as , , , , , , , ,

Background 38 CPM
Total 19,262 CPM *
Beta+Gamma 14,116 CPM *
Gamma 1,392 cpm *

* values shown minus background (e.g. 19300 CPM total becomes 19,262 CPM after 38 CPM removed)

This is how we figure it out:

Alpha = Total – Beta+Gamma
Beta = Beta+Gamma – Gamma
Gamma = Gamma

We can replace the words for real values from above:
Alpha = (19262 CPM) – (14116 CPM) = 5146 CPM
Beta = (14116 CPM) – (1392 CPM) = 12724 CPM
Gamma = (1392 CPM) = 1392 CPM

The results sum back to the total, which helps us check our work:
Alpha + Beta + Gamma = 5146 CPM + 12724 CPM + 1392 CPM = 19262 CPM
——————————————————————————————

Here’s that bit about the copper lol I added it for fun, but it is correct.
Sheilding HVL of Copper: 10.2 mm
Thickness of Sample: ~4mm
Most Common Energy of Gamma: 214Bi 609.31 keV at 44.8%
e^-log(2)4mm/10.2mm = 0.76199, where d/dx e^-((ln(2)/10.2mm)*x) = (4^((-2+x)/x) log(2))/x^2

## Simple Decay Equation – Example (Polonium 210)

Filed under Science

How to calculate the current activity of a source given the activity at one point, the time which has elapsed, and the decay constant.

Activity_now = Activity_then * e^-((ln2/halflife)*elapsed_time)

Now, enter into your calculator for activity of 1000Bq, halflife of 20min, and elapsed time of 40min:

1000 * e ^ – ( ( ln(2) / 20 ) * 40 ) )